How To Get An HTML File Using Python?

I am not very familiar with Python. I am trying to extract the artist names (for a start :)) from the following page: http://www.infolanka.com/miyuru_gee/art/art.html. How do I re

Solution 1:

Example using urlib and lxml.html:

import urllib
from lxml import html

url = "http://www.infolanka.com/miyuru_gee/art/art.html"
page = html.fromstring(urllib.urlopen(url).read())

for link in page.xpath("//a"):
    print "Name", link.text, "URL", link.get("href")

output >>
    [('Aathma Liyanage', 'athma.html'),
     ('Abewardhana Balasuriya', 'abewardhana.html'),
     ('Aelian Thilakeratne', 'aelian_thi.html'),
     ('Ahamed Mohideen', 'ahamed.html'),
    ]

Solution 2:

I think "eyquem" way would be my choice too, but I like to use httplib2 instead of urllib. urllib2 is too low level lib for this work.

import httplib2, re
pat = re.compile('<DT><a href="[^"]+">(.+?)</a>')
http = httplib2.Http()
headers, body = http.request("http://www.infolanka.com/miyuru_gee/art/art.html")
li = pat.findall(body)
print li

Solution 3:

1. Use urllib2 to get the page.

2. Use BeautifulSoup to parse the HTML (the page) and get what you want!

Solution 4:

Check this my friend

import urllib.request

import re

pat = re.compile('<DT><a href="[^"]+">(.+?)</a>')

url = 'http://www.infolanka.com/miyuru_gee/art/art.html'

sock = urllib.request.urlopen(url).read().decode("utf-8")

li = pat.findall(sock)

print(li)

Solution 5:

Or go straight forward:

import urllib

import re
pat = re.compile('<DT><a href="[^"]+">(.+?)</a>')

url = 'http://www.infolanka.com/miyuru_gee/art/art.html'
sock = urllib.urlopen(url)
li = pat.findall(sock.read())
sock.close()

print li